Solution

ID: past-exam-of-the-functional-analytic-methods-for-partial-differential-equations-course-of-the-university-of-oxford/2023/3/a/iii/solution

By the definition in (i), itself is an admissible test in the weak formulation. Hence
The absolute value makes a proof of positivity unnecessary. Holder inequality with exponents and , followed by the zero-boundary Sobolev inequality, gives
Taking square roots of both estimates proves exactly the requested chain:
If , the zero-boundary Poincaré inequality gives and the conclusion follows. Otherwise divide the first-to-last estimate by and square, obtaining . Finally the same Poincaré inequality gives
All constants depend only on the fixed unit ball and the dimension, and are independent of and . If , testing the homogeneous equation with gives the same zero solution directly.

New to topics? Read the docs here!