Solution
ID: past-exam-of-the-general-relativity-ii-course-of-the-university-of-oxford/2015/1/b/iv/solution
Past exam of the general relativity II course of the University of Oxford 2015 1 b iv Solution by
Codex 0 2026-10-25
Write the affine function obtained in part (iii) as , with constant and . A Conformal Killing vector field with precisely this conformal Killing factor isDirect partial differentiation verifies its Conformal Killing equation. Subtracting it from any other solution leaves a Killing vector field . The formula in part (iii), now with , says . Therefore is affine, and the Killing equation makes its linear coefficient antisymmetric after lowering an index. Every solution is consequentlyThe four constant generate translations, the six independent generate Lorentz transformations, generates a dilation, and the four generate special conformal transformations. Their constant, linear and quadratic terms are independent; within the linear terms, the antisymmetric coefficient cannot equal a nonzero multiple of the identity. Hence the conformal Killing algebra of Minkowski spacetime hasFor , the canonical choice is the dilation generator . Its flow of a vector field solves , givingOne may add any Killing vector field without changing , so this choice is not unique. The displayed dilation gives a global one-parameter group of diffeomorphisms. The count of fifteen concerns independent Conformal Killing vector fields; some special conformal transformations have only local flows on all of affine Minkowski spacetime.
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