 Solution

ID: past-exam-of-the-geometry-course-of-the-university-of-oxford/2009/a/2/ii/solution

g_{X} = 0

2 = d (2 - 2 g_{Y}) - R

, where

R \geq 0

. If

g_{Y} \geq 1

, the right side is nonpositive, a contradiction. Therefore

g_{Y} = 0.

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