Solution

ID: past-exam-of-the-graph-theory-and-probabilistic-combinatorics-course-of-the-university-of-oxford/2011/a/2/b/i/solution

Take a proper colouring and orient every edge from its lower-coloured endpoint towards its higher-coloured endpoint. Along a directed path the colour strictly increases, so such a graph path has at most vertices. A directed cycle is impossible for the same reason. Thus

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