Solution

ID: past-exam-of-the-lie-algebras-and-representation-theory-of-symmetric-groups-course-of-the-university-of-oxford/2007/b/5/c/solution

For a cycle type , the Murnaghan–Nakayama rule is
The sum is over partitions whose diagrams remain after removing the specified border strip; is the remaining cycle type, and the recursion ends with the empty character equal to one. At the identity, . Incompatible total sizes contribute zero.
For shape and a transposition, a horizontal strip in the bottom row leaves with positive sign; a vertical strip in the right column leaves with negative sign. Both remaining dimensions are one. Thus

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