 Solution

ID: past-exam-of-the-mathematical-methods-i-course-of-the-university-of-oxford/2014-resit/12/ii/solution

[A \times (B \times C)]_{i} = ϵ_{ijk} ϵ_{k l m} A_{j} B_{l} C_{m} = (δ_{i l} δ_{jm} - δ_{im} δ_{j l}) A_{j} B_{l} C_{m} .

A \times (B \times C) = B (A \cdot C) - C (A \cdot B) .

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