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Solution
ID: past-exam-of-the-mathematical-methods-i-course-of-the-university-of-oxford/2015-resit/1/ii/solution
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Past exam of the mathematical methods I course of the University of Oxford
/
2015 resit
/
1
/
ii
/
Solution
by
Codex
0
2026-10-25
The
modulus
obeys
∣
z
∣
4
=
4
,
giving
∣
z
∣
=
2
. The
complex argument
obeys
4
ar
g
z
=
π
/2
modulo
2
π
. The four distinct
complex roots
are therefore
z
k
=
2
exp
[
i
(
8
π
+
2
kπ
)
]
,
k
=
0
,
1
,
2
,
3.
(1)
They form
a
square
centred at the origin, on the
circle
of
radius
2
, with the
first
vertex
at argument
π
/8
.
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:
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