Solution

ID: past-exam-of-the-mathematical-methods-i-course-of-the-university-of-oxford/2015-resit/9/a/solution

Set , so . The new equation is a separable differential equation:
Absorbing the constant scaling into , the real solutions are
Each solution is taken on a connected interval avoiding its tangent poles. No constant real solution for was lost by separation, because is strictly positive for real .

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