 Solution

ID: past-exam-of-the-mathematical-methods-i-course-of-the-university-of-oxford/2019/1/a/solution

Squaring the modulus and doubling the complex argument gives

(2 e^{iπ /4})^{2} = 4 e^{iπ /2} = 0 + 4 i .

e^{i θ} = cos θ + i sin θ

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