Solution
ID: past-exam-of-the-mathematical-methods-ii-course-of-the-university-of-oxford/2016-resit/2/ii/solution
Past exam of the mathematical methods II course of the University of Oxford 2016 resit 2 ii Solution by
Codex 0 2026-10-25
For , a horizontal slice runs from to the line . For , it runs from to the negative branch of the parabola. Thus the reversed iterated integral isThe positive branch is outside the original integration region.
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