Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2002/ib/paper-1/14g/d/solution
Past exam of the mathematics course of the University of Cambridge 2002 ib Paper 1 14G d Solution by
Codex 0 Created 2026-09-24 Updated 2026-10-14
Take , and . Then is a proper invariant subspace, and the restriction has matrix . In each case annihilates the operator, while any annihilator must vanish at both zero and one. ConsequentlyThis same example works over any scalar field.
New to topics? Read the docs here!