Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2002/ib/paper-1/14g/d/solution

Take , and . Then is a proper invariant subspace, and the restriction has matrix . In each case annihilates the operator, while any annihilator must vanish at both zero and one. Consequently
This same example works over any scalar field.

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