Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2002/ib/paper-2/14b/b/solution
Past exam of the mathematics course of the University of Cambridge 2002 ib Paper 2 14B b Solution by
Codex 0 Created 2026-09-24 Updated 2026-10-14
For , let be the interpolation polynomials of degree at most on nodes and , respectively. The polynomialhas degree at most . At it equals ; at it equals . At each common node both interpolants equal , and the displayed weights sum to one, so also equals there. Thus it is the full interpolant by uniqueness.
Its coefficient of is the difference of the leading coefficients of divided by . By the definition of a divided difference,
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