Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2002/ib/paper-2/14b/b/solution

For , let be the interpolation polynomials of degree at most on nodes and , respectively. The polynomial
has degree at most . At it equals ; at it equals . At each common node both interpolants equal , and the displayed weights sum to one, so also equals there. Thus it is the full interpolant by uniqueness.
Its coefficient of is the difference of the leading coefficients of divided by . By the definition of a divided difference,

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