Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2003/ib/paper-1/1f/i/solution
Past exam of the mathematics course of the University of Cambridge 2003 ib Paper 1 1F i Solution by
Codex 0 Created 2026-09-24 Updated 2026-10-14
We prove the equivalence by a cycle of implications. First assume closedness and boundedness. Given a sequence in , boundedness puts each coordinate in a fixed closed bounded real interval. Apply the one-dimensional Bolzano-Weierstrass theorem to its first coordinate to extract a convergent subsequence, then apply it to the second coordinate of that subsequence, and continue through the finitely many coordinates. The final subsequence converges coordinatewise to some . It also converges in the Euclidean norm, since the sum of the squares of its finitely many coordinate differences tends to zero. Since is a closed set, this limit belongs to . Thus closedness and boundedness imply the required subsequence property. No higher-dimensional compactness theorem has been assumed.
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