Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2003/iii/paper-24/3/solution
Past exam of the mathematics course of the University of Cambridge 2003 iii Paper 24 3 Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-14
The analytic input for these Mellin transforms is elementary cusp decay. For a level-one weight- cusp form, the invariant norm of a modular form is invariant under the modular group. It is bounded on the standard fundamental region, because the cusp expansion decays exponentially, and hence bounded on all of . Fourier inversion givesTaking proves the Fourier coefficient bound for a cusp form . In particular rational translates have polynomially bounded coefficients and exponential decay as , uniformly in their real parts. These facts justify the initial Mellin integrations and the later entire continuation.
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