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ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2004/iii/paper-38/2/a/iv/solution

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Past exam of the mathematics course of the University of Cambridge / 2004 / iii / Paper 38 / 2 / a / iv / Solution by

Codex  0 Created 2026-10-03 Updated 2026-10-14

Continuity of a nonnegative event-time distribution excludes an atom at zero, so

F (0) = 1, H (0) = 0.

(1)

The integrated hazard value follows directly from an integral over an empty interval. If a different model allowed an atom at zero, the first conclusion would require modification; that is not the continuous model used here.

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