Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2005/iii/paper-5/3/i/solution
Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 5 3 i Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-14
A nonnegative sublinear operator satisfies and almost everywhere. It has weak type (1,1) if there is a finite constant , independent of the function and threshold, such thatFor a signed or complex output use in the level set. The bound controls the distribution of large values; it does not assert that is integrable.
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