Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2005/iii/paper-79/3/c/solution

For the broad right layer take and , so inside the interval. Its leading equation is , with . One integration gives . The positive derivative branch produces the integral parametrization in the hint.
Matching to a small, nearly flat plateau requires and at the inner edge, so the leading integration constant is . A positive order-one would leave a nonzero slope as ; a negative one would prevent that limit. For , integration with gives
Its zero is at , namely . Near that edge it has the fourth-power overlap obtained in solution. The neglected reaction term becomes comparable to when , precisely where the thinner transition must restore it. The sketch in solution shows the plateau and both right-hand regions; extending the quartic profile past its inner edge would fail to match the positive plateau.

New to topics? Read the docs here!