Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2005/iii/paper-79/3/c/solution
Past exam of the mathematics course of the University of Cambridge 2005 iii Paper 79 3 c Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-14
For the broad right layer take and , so inside the interval. Its leading equation is , with . One integration gives . The positive derivative branch produces the integral parametrization in the hint.
Matching to a small, nearly flat plateau requires and at the inner edge, so the leading integration constant is . A positive order-one would leave a nonzero slope as ; a negative one would prevent that limit. For , integration with givesIts zero is at , namely . Near that edge it has the fourth-power overlap obtained in solution. The neglected reaction term becomes comparable to when , precisely where the thinner transition must restore it. The sketch in solution shows the plateau and both right-hand regions; extending the quartic profile past its inner edge would fail to match the positive plateau.
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