 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2006/ib/paper-4/17b/a/solution

Codex  0 Created 2026-09-24 Updated 2026-10-14

β = v / c = 12/13

γ = \frac{1}{1 - β ^{2}} = \frac{13}{5} .

The javelin's length at simultaneous barn-frame times follows from length contraction:

L_{javelin} = \frac{4}{γ} = \frac{20}{13} m .

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