Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2006/ib/paper-4/8d/b/solution

Keep the original four-node interpolation polynomial . The correction must vanish at all four original nodes, so a degree-at-most-four interpolant has the form
Since and the product at is , matching the new value gives , hence . Expanding yields
It takes the values at the five nodes. The same root-count argument proves uniqueness of this interpolation polynomial.

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