Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2007/iii/paper-29/2/a/solution

Adjoin to the complex upper half-plane. Ordinary points retain their usual neighborhoods. At a rational boundary point , a neighborhood basis consists of together with , with arbitrarily large. Different choices of change it by a translation and sign, so give the same neighborhood system. Give the quotient topology. The modular group acts properly discontinuously on ; its modular cusp neighborhoods descend to punctured neighborhoods with their modular cusp point filled in. This quotient is Hausdorff: interior orbits can be separated by proper discontinuity, and a sufficiently high modular cusp neighborhood avoids any prescribed compact interior neighborhood.
Away from fixed points of the effective group , a small disk is disjoint from its nonidentity translates, so its coordinate gives a holomorphic quotient coordinate. At an elliptic fixed point , use
Its effective stabilizer rotates by an th root of unity, where at and at . The quotient coordinate is , not . All rational boundary points lie in one modular cusp class. At infinity the stabilizer acts by , and
is a punctured-disk coordinate; adjoining fills in the modular cusp. These charts and their holomorphic transition maps define the complex structure of the compactified modular curve.
For compactness use the standard region
Its part with , , is compact: the imaginary part is at least . The quotient of its upper tail, with its two vertical sides identified and infinity added, is the closed disk . These two compact images cover , including the boundary-edge identifications. Thus is a compact Riemann surface.
The function also extends over the modular cusp with one simple pole, since . Its local expressions at elliptic points descend to holomorphic functions of . By Question 1 it maps the remaining quotient bijectively onto , so its extension is a degree-one holomorphic map . A degree-one map of compact Riemann surfaces is biholomorphic: any local ramification would already give degree at least two. Therefore is the Riemann sphere; this will also identify the base genus in Question 5.

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