Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2007/iii/paper-34/1/c/solution

Omit indices of probability zero. The support of a positive operator of every remaining lies within that of , because is a positive sum containing . Thus is finite.
First suppose , so all quantities are finite. Expand the trace definitions of quantum relative entropy:
Therefore Donald's identity is
If the support condition on fails, at least one positive-weight also fails it. The left side and the final term on the right are then , while the first right-hand sum remains finite. The equality is valid in this extended sense, without taking any undefined difference of infinities.

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