 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2008/ib/paper-2/17b/ii/solution

Codex  0 Created 2026-09-24 Updated 2026-10-14

The current vector along the bar points downward. Integrating the Lorentz force along its length gives

F = I (- ℓ \hat{y}) \times (B \hat{z}) = - I B ℓ \hat{x} = - \frac{B ^{2} ℓ ^{2} v}{R} \hat{x} .

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