 Solution

Smaller mean Bayesian deviance indicates better average likelihood fit. Model B has the smallest $\overline{D}$, improving on A by $3.9$ and on C by $3.1$. Model C has the smallest effective parameter count in DIC, reflecting its shared timing and growth coefficients. Model B's hierarchical covariance parameters and residual flexibility contribute to a larger effective count than C.

Adding fit and complexity gives the reported deviance information criterion: A has $260.1$, B $258.1$, and C $255.6$. Thus DIC favors Model C, whose simpler shape more than compensates for its slightly worse mean fit than B. The differences are modest, and the criteria must use the same observation likelihood and deviance convention. These numbers are not posterior model probabilities; predictive assessment remains useful.