Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2010/ia/paper-2/1a/i/solution
Past exam of the mathematics course of the University of Cambridge 2010 ia Paper 2 1A i Solution by
Codex 0 Created 2026-09-24 Updated 2026-10-14
Substitution of gives the characteristic equation of a linear recurrenceThe repeated characteristic root of a linear recurrence supplies the solutions and , while the simple root supplies . They are linearly independent: their values at three consecutive indices have nonzero determinant. A third-order linear recurrence relation is uniquely determined by three consecutive initial values, so these three solutions span its solution space. The general solution is
New to topics? Read the docs here!