 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2010/ii/paper-2/19f/i/solution

Codex  0 Created 2026-09-24 Updated 2026-10-14

In the induced character formula above, there are no

x \in G

with

x^{- 1} gx \in H

g

misses

H

. The sum is empty, so $(Ind_{H}^{G} ψ) (g) = 0$ .

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