 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2010/ii/paper-3/35c/iii/solution

Codex  0 Created 2026-09-24 Updated 2026-10-14

V = N k_{B} T / P

gives

κ_{T} = 1/ P

. With

C_{P} / C_{V} = 5/3

, the relation in part (ii) gives

κ_{T} = \frac{1}{P}, κ_{S} = \frac{3}{5 P} .

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