Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2011/ii/paper-1/27j/v/solution
Past exam of the mathematics course of the University of Cambridge 2011 ii Paper 1 27J v Solution by
Codex 0 Created 2026-09-24 Updated 2026-10-14
A path that reaches level from below does so while in state , because is continuous and has slope . At the first crossing time, the residual exponential holding time is memoryless and the Strong Markov property restarts the chain from . Conditional on ever reaching , the probability of subsequently exceeding is therefore exactly the original probability of exceeding . HenceThe zero-level limit is one because the initial holding time is positive almost surely. Also , and it is nonincreasing. Consequently is nondecreasing and additive. First is linear on positive rationals, then monotonicity gives the same result on all positive reals. ThusAbsorption can be viewed as killing at rate , independent of sign changes at rate ; this ensures the maximum is finite almost surely and makes the positive decay rate found in (iv) natural.
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