 Solution

Yes. Choose a global differential one-form $\beta$ with $d\beta =\sigma$, and use the cotangent fiber translationIt is a diffeomorphism with inverse $T_{-\beta }$, and $\pi \circ T_{\beta }=\pi$. Directly from the Liouville one-form,The sign convention $\omega =-d\alpha$ therefore givesThus $T_{\beta }:(T^{\ast }X,\omega )\to (T^{\ast }X,{\omega }_{\sigma })$ is the required symplectomorphism. Equivalently, $T_{-\beta }^{\ast }\omega ={\omega }_{\sigma }$ gives the inverse direction. This translation equivalence of exact twisted cotangent bundles is global even when $X$ is not compact; no completeness argument for a Moser theorem flow is needed.