Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2012/iii/paper-18/2/ii/solution

For the intended complex unit circle, put and , with . The complete family of semicharacters of a complex lattice is
To obtain this, the identity at zero gives ; on each coordinate axis the alternating form vanishes, so and , also for negative integers. Combining the axes gives the factor . Conversely, for , , the quotient of the proposed values is , which equals . Hence every displayed formula is a semicharacter of a complex lattice and none are missing.
The original PDF actually puts in its definition of . Under that literal reading , so there are exactly four solutions, given by the same formula with . Under either reading the specified choice is .

New to topics? Read the docs here!