Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2013/iii/paper-27/1/ii/solution

The capacity in this question is harmonic capacity from infinity in the upper half-plane, which has units of length; it is distinct from half-plane capacity, which has units of length squared.
Here is a proof of existence that also works with irregular real attachments. The function
is bounded and harmonic on , by the Strong Markov property and the mean-value characterization of harmonic functions. Therefore is a bounded harmonic function on the complex upper half-plane, with a Poisson kernel representation
The boundary function vanishes outside a bounded interval. Indeed, far enough along either real ray the original domain contains a half-disc neighbourhood, and extends there; the probability of hitting the bounded hull before the real boundary tends to zero as the starting point approaches that ray. Applying the same dominated-limit calculation as in part (i) yields
When the intrinsic boundary pieces landing on the hull are identified, is their indicator almost everywhere and this is the length of their image under . For ordinary finite slit hulls this is exactly the image of , since real attachment endpoints have zero harmonic measure. The Poisson representation avoids requiring that boundary identification in the general existence argument.
If , couple the two exit events using the same planar Brownian motion, stopped at its first hit of the real axis. Any path that hits before the real axis also hits before the real axis. Consequently
and taking the limits proves monotonicity of this capacity.
For a half-disc of radius centred at , the mapping-out function is
Its semicircular boundary maps onto , of length . Hence its harmonic capacity from infinity in the upper half-plane is . With
enclose in such a half-disc and use monotonicity. Letting the enclosing radius decrease to the infimum proves
The same conclusion holds if radius is instead measured about a specified real centre.

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