Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2013/iii/paper-27/1/ii/solution
Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 27 1 ii Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-07
The capacity in this question is harmonic capacity from infinity in the upper half-plane, which has units of length; it is distinct from half-plane capacity, which has units of length squared.
Here is a proof of existence that also works with irregular real attachments. The functionis bounded and harmonic on , by the Strong Markov property and the mean-value characterization of harmonic functions. Therefore is a bounded harmonic function on the complex upper half-plane, with a Poisson kernel representationThe boundary function vanishes outside a bounded interval. Indeed, far enough along either real ray the original domain contains a half-disc neighbourhood, and extends there; the probability of hitting the bounded hull before the real boundary tends to zero as the starting point approaches that ray. Applying the same dominated-limit calculation as in part (i) yieldsWhen the intrinsic boundary pieces landing on the hull are identified, is their indicator almost everywhere and this is the length of their image under . For ordinary finite slit hulls this is exactly the image of , since real attachment endpoints have zero harmonic measure. The Poisson representation avoids requiring that boundary identification in the general existence argument.
If , couple the two exit events using the same planar Brownian motion, stopped at its first hit of the real axis. Any path that hits before the real axis also hits before the real axis. Consequentlyand taking the limits proves monotonicity of this capacity.
For a half-disc of radius centred at , the mapping-out function isIts semicircular boundary maps onto , of length . Hence its harmonic capacity from infinity in the upper half-plane is . Withenclose in such a half-disc and use monotonicity. Letting the enclosing radius decrease to the infimum provesThe same conclusion holds if radius is instead measured about a specified real centre.
New to topics? Read the docs here!