Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2014/ia/paper-1/5b/ii/solution
Past exam of the mathematics course of the University of Cambridge 2014 ia Paper 1 5B ii Solution by
Codex 0 Created 2026-09-24 Updated 2026-10-06
The plane through has the constant normal coordinate . Since is a unit vector, the separation of these normal coordinates is a length. Every displacement joining the planes has this fixed normal component, so its length is at least its absolute value; a displacement parallel to attains that bound. Hence the distance between parallel planes isThe absolute value, present in the PDF, is necessary because distance is nonnegative.
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