 Solution

Give each permanent member weight seven, each nonpermanent member weight one, and use the strict threshold $t=38$. If a coalition omits a permanent member, its weight is at most $4\cdot 7+10=38$, so it loses. If it includes all five permanent members and $r$ others, its weight is $35+r$, which exceeds 38 exactly when $r\ge 4$. These are precisely the required winning coalitions. Thus a weighted voting game representation isThe strict-threshold convention is important: in the alternative convention requiring weight at least the quota, the quota is 39.