Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2015/iii/paper-9/6/a/solution

With only available, use a distributional weak solution: for every test function require
All terms are meaningful because the smooth coefficients are bounded on the compact support of the test function and is locally integrable. This is exactly as an identity of distributions. No first weak derivative of is assumed in this definition, and no boundary condition is being imposed.

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