 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2016/ib/paper-4/18c/a/solution

Codex  0 Created 2026-09-24 Updated 2026-10-06

ω = \nabla \times u

\nabla \times ω = \nabla (\nabla \cdot u) - \nabla^{2} u .

\nabla \cdot u = 0

, so

\nabla \times ω = - \nabla^{2} u .

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