Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2016/iii/paper-103/1/c/ii/solution

The identity from part (a) shows that each Young–Jucys–Murphy element belongs to the Gelfand–Tsetlin algebra. Conversely, lies in the centralizer of in . Applying the preceding Olshanskii centralizer lemma at level gives
Induction, beginning with , proves . Thus
Here every generated algebra is unital; causes no problem.
To deduce simple branching, use Maschke's theorem: complex representations of finite groups are semisimple modules. The Artin–Wedderburn theorem identifies
where runs over the irreducible -modules. Write their restrictions as
By Schur lemma, the centralizer in the displayed algebra is
with zero multiplicities omitted. Part (i) makes this algebra commutative, whereas a full matrix algebra of size at least two is noncommutative. Consequently every restriction multiplicity is or . This proves multiplicity-free restriction at each step, with no use of the branching rule in the centralizer proof.

New to topics? Read the docs here!