 Solution

Let $f_n$ be Borel measurable and converge pointwise to the finite real value $f$. For every real $a$,If $f(x)>a$, choose a rational $r$ strictly between them; convergence puts $f_n(x)>r$ eventually. Conversely eventual strict inequality $f_n(x)>r>a$ implies $f(x)\ge r>a$. The right side belongs to $\mathcal{E}$ by its countable union/intersection operations. Since these half-lines generate the Borel sigma-algebra, $f$ is a Borel measurable function.