Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2017/iii/paper-115/4/b/solution
Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 115 4 b Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-05
Let be the projections. The derivative of the two projections identifies the tangent bundle withTake the direct sum of the two pullback connections. This is the product affine connection. In product coordinates , its only nonzero Christoffel symbols are the two blocks inherited from the factors; all mixed coefficients are zero.
To make the connection on arbitrary fields explicit, write and , allowing all coefficients to depend on both variables. ThenThe terms and include derivatives in both factors. Omitting these cross derivatives for fields with variable coefficients would not define a connection.
The formula is real-bilinear, linear over smooth functions in , and obeys the Leibniz rule in . Under a change of product coordinates each block has the factor's connection transformation law, so the local formulas agree; equivalently the pullback connection construction already guarantees this gluing.
A field on one factor has a canonical lift to the product. Opposite-factor lifts commute, and their mixed covariant derivatives vanish. For such lifted fields the coefficient derivatives reduce to their factor derivatives, givingThese values determine the connection uniquely: lifted coordinate frames span locally, and the connection's product rules determine its action on all their smooth linear combinations.
New to topics? Read the docs here!