 Solution

Use conventional mean longitudes $\lambda$ and take the positive integers $p,q$ in lowest terms. Rotational invariance requires the angular coefficients of a resonant argument to sum to zero. Since the inner planet has zero orbital eccentricity, the eccentricity-type term involving its undefined apsidal angle has zero amplitude. The surviving outer-eccentricity argument isIts leading disturbing function term is proportional to $e_c^q\cos {\varphi }_{bc}$. Near the period commensurability, $(p+q)n_c-p{n}_b$ is small, so the resonant argument is slow and repeated perturbations can add coherently. Trapping produces resonant-argument libration, rather than circulation, with $(p+q)n_c-p{n}_b-q{\dot{\varpi }}_c\simeq 0$.

A near-integer period ratio alone does not prove mean-motion resonance: the diagnostic is bounded resonant-argument libration. At $e_c=0$ this eccentric resonant term vanishes and ${\varpi }_c$ is undefined. If $p,q$ have a common factor, reduce the ratio first; the unreduced $q$ is not the actual lowest resonance order.