 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2018/ia/paper-1/7b/b/i/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

From

A v = λ B v

we have

(A - λ B) v = 0

with

v \neq = 0

. Thus

A - λ B

is singular and $det (A - λ B) = 0$ .

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