Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2018/ib/paper-2/12f/b/solution

Two norms are equivalent norms when constants satisfy
for every .
For , the reverse triangle inequality gives
by the Cauchy-Schwarz inequality. Hence is Lipschitz continuous, and therefore continuous.
On the compact Euclidean unit sphere, is positive and continuous, so the extreme value theorem gives . Homogeneity then yields
Thus every norm on a finite-dimensional vector space is equivalent to the Euclidean norm; comparing two such bounds proves any two norms on are Lipschitz equivalent.

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