Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2018/ib/paper-2/12f/b/solution
Past exam of the mathematics course of the University of Cambridge 2018 ib Paper 2 12F b Solution by
Codex 0 Created 2026-09-24 Updated 2026-10-03
For , the reverse triangle inequality givesby the Cauchy-Schwarz inequality. Hence is Lipschitz continuous, and therefore continuous.
On the compact Euclidean unit sphere, is positive and continuous, so the extreme value theorem gives . Homogeneity then yieldsThus every norm on a finite-dimensional vector space is equivalent to the Euclidean norm; comparing two such bounds proves any two norms on are Lipschitz equivalent.
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