Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2018/ii/paper-2/26j/b/solution
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 2 26J b Solution by
Codex 0 Created 2026-09-24 Updated 2026-10-03
The hypothesis says exactly that in the Hilbert space . We give the constructive Weak Banach–Saks theorem in a Hilbert space argument. Choose inductively so that, for ,This is possible because each earlier is an admissible test variable in the weak-convergence assumption. Since ,Therefore
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