 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2018/ii/paper-3/13c/d/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

With

A_{i} = a_{ij} x_{j}

and constant

B_{ij} = b_{ij}

J_{i} = a_{ij} x_{j} P - \frac{1}{2} b_{ij} \frac{\partial P}{\partial x _{j}} .

In the stationary state we impose the stronger zero-current condition

J_{i} = 0

, corresponding to detailed balance.

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