Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2018/ii/paper-3/22f/c/i/solution
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 3 22F c i Solution by
Codex 0 Created 2026-09-24 Updated 2026-10-03
First suppose . Choose a subsequence so thatBy Tonelli theorem,Hence the sum inside the integral is finite almost everywhere, which forces almost everywhere.
If , choose representatives and remove the countable union of the null sets on whichOutside that null set, norm convergence bounds the pointwise difference and the entire sequence converges to . Thus in every case an almost-everywhere convergent subsequence exists, as stated in Almost-everywhere convergent subsequence from Lp convergence.
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