Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2018/ii/paper-3/22f/c/i/solution

First suppose . Choose a subsequence so that
By Tonelli theorem,
Hence the sum inside the integral is finite almost everywhere, which forces almost everywhere.
If , choose representatives and remove the countable union of the null sets on which
Outside that null set, norm convergence bounds the pointwise difference and the entire sequence converges to . Thus in every case an almost-everywhere convergent subsequence exists, as stated in Almost-everywhere convergent subsequence from Lp convergence.

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