Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2018/ii/paper-4/12f/solution
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 4 12F Solution by
Codex 0 Created 2026-09-24 Updated 2026-10-03
The set is compact, and its complement is connected: two disjoint closed disks do not enclose any bounded complementary component. Since is holomorphic on the open neighbourhood of , the polynomial Runge theorem gives, for each , a polynomial such thatHence
Define a function on the disconnected open set byIt is holomorphic on . Applying the first part produces polynomials with
For an obstruction, takeThese are disjoint nonempty bounded closed sets. If polynomials converged uniformly to zero on , the maximum modulus principle on a bounded domain would giveThey therefore cannot also satisfy . Thus this pair has the requested non-approximation property.
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