Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2018/ii/paper-4/5j/solution
Past exam of the mathematics course of the University of Cambridge 2018 ii Paper 4 5J Solution by
Codex 0 Created 2026-09-24 Updated 2026-10-03
With Control as the reference group, the fitted normal linear model has meanThus the control-group rate is , while the treatment-group rate is . The estimates areandweight units per day. The control slope has and , so there is no statistically significant evidence of weight loss over time in the control group at conventional significance levels.
The plotted regression residuals for each mouse form smooth time patterns rather than an unstructured cloud: nearby observations on the same mouse have similar residuals, and the mice also show persistent individual offsets. This is strong evidence of autocorrelation and omitted mouse-level variation. The ordinary linear model treats all 400 measurements as independent after accounting for cage, so it commits pseudoreplication and will generally underestimate the coefficient standard errors. The reported -tests and -values should therefore not be trusted. A random-intercept linear mixed model with a within-mouse correlation structure would respect the repeated-measures design.
New to topics? Read the docs here!