Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2018/iii/paper-214/1/b/ii/solution
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 214 1 b ii Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-05
For each of the coordinate faces of , define the increasing event that an open path in a graph lying in joins to . Their union is exactly the event of connection from to within . The bond percolation law and the centered boxes are invariant under coordinate permutations and sign changes, so all events have the same probability.
Apply the square-root trick for positively associated events from part (a), with in place of the number of events. If , part (b.i) gives, for every ,In particular this holds for the left and right faces, and it proves the stronger statement in which each connecting path in a graph stays inside the outer box.
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