 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2019/ia/paper-1/1c/b/solution

Codex  0 Created 2026-09-24 Updated 2026-09-29

Since

(1 + i) / (1 - i) = i

and

(1 + i)^{2} = 2 i

\frac{( 1 + i ) ^{2019}}{( 1 - i ) ^{2017}} = i^{2017} (1 + i)^{2} = i (2 i) = - 2 .

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