Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2019/ii/paper-1/14a/b/solution

Let solve the equation represented by the original symbol and define a dependent-variable rescaling of a Papperitz symbol
with a consistent local choice of branch. Near , the multiplier is a nonzero analytic factor times , so both exponents at increase by . Near , it is a nonzero analytic factor times , so both exponents at decrease by . It is analytic and nonzero near , so the exponents there are unchanged. Therefore the transformed equation has symbol
The opposite shifts also preserve the Fuchs relation.

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