Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2019/ii/paper-1/14a/b/solution
Past exam of the mathematics course of the University of Cambridge 2019 ii Paper 1 14A b Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-29
Let solve the equation represented by the original symbol and define a dependent-variable rescaling of a Papperitz symbolwith a consistent local choice of branch. Near , the multiplier is a nonzero analytic factor times , so both exponents at increase by . Near , it is a nonzero analytic factor times , so both exponents at decrease by . It is analytic and nonzero near , so the exponents there are unchanged. Therefore the transformed equation has symbolThe opposite shifts also preserve the Fuchs relation.
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