Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2019/ii/paper-1/27k/b/iii/solution

First, . For every ,
It cannot vanish: if for some , then
would imply for every positive integer , contradicting continuity at zero. Thus . Since every characteristic function has modulus at most one,
Now set . It is continuous, nonnegative, and additive:
The classification of a continuous additive function on the nonnegative real numbers gives , where . Consequently

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