 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2019/ii/paper-2/13a/b/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

For

n \neq = 0

\frac{d}{d t} (e^{- t} - 1)_{t = 2 πin} = - e^{- 2 πin} = - 1.

Res_{t = 2 πin} \frac{t ^{- z}}{e ^{- t} - 1} = - (2 πin)^{- z} .

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